Topics

Name of the Batsman |
Number if matchesplayed in the tournament |
Average runs scoredin the tournament |
Total balls facedin the tournament |
Strike ratein the tournament |

M |
22 |
56 |
- |
- |

N |
18 |
- |
- |
153.6 |

O |
- |
- |
900 |
110 |

P |
- |
36 |
- |
84 |

Q |
- |
- |
- |
140 |

R |
24 |
51 |
1368 |
- |

(i) Strike rate = \( \large\frac{Total runs scored}{ Total balls faced} \) x 100

(ii) All the given batsmen could bat in all the given matches played by them.

(iii) Few values are missing in the table (indicated by -- ). A candidate is expected to calculate the missing value, if it is required to answer the given questions, on the basis of the given data and information.

A) 1800 |

B) 1500 |

C) 1700 |

D) 1600 |

E) 1400 |

Correct Answer:

D) 1600 |

Description for Correct answer:

Let the number of balls faced by him in first 11 matches = x

Total runs scored in first 11 matches = \( \frac{83x}{100} \)

Total runs scored in last 11 matches = \( \frac{71x}{100} \)

According to question,

= \( \frac{83x}{100} + \frac{71x}{100} = 22 \times 56 \)

= \( \frac{154x}{100} = 22 \times 56 \)

= \( x = 800 \)

Total number of balls faced by him in the tournament = \( 800 + 800 = 1600 \)

Let the number of balls faced by him in first 11 matches = x

Total runs scored in first 11 matches = \( \frac{83x}{100} \)

Total runs scored in last 11 matches = \( \frac{71x}{100} \)

According to question,

= \( \frac{83x}{100} + \frac{71x}{100} = 22 \times 56 \)

= \( \frac{154x}{100} = 22 \times 56 \)

= \( x = 800 \)

Total number of balls faced by him in the tournament = \( 800 + 800 = 1600 \)

Part of solved RBI Grade B questions and answers : Exams >> Bank Exams >> RBI Grade B

Comments

Similar Questions