A 476 m long moving train crosses a pole in 14 sec. The length of a platform is equal to the distance covered by the train in 20 sec. A man crosses the same platform in 7 m and 5 sec. What is the Speed of the man in m/s ?
Correct Answer: Description for Correct answer:
Speed of the traub = \( \frac{476}{14} = 34 m/s\)
Length of the platform = \( 34 \times 20 = 680 m \)
Speed of the man = \( \frac{680}{425} = 1.6 m/s \)
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