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A vessel contains a mixture of milk and water in the respective ratio of 3 : 1. 32 litre of mixture was taken out and replaced with the same quantity of milk so that the resultant ratio between the quantities of milk and water in the mixture was 4 . : 1 respectively. If 10 litre of mixture is again taken out from the vessel, what is the resultant quantity of water in the mixture ? (in litre)

A) 24
B) 30
C) 20
D) 36
E) 32

Correct Answer:


B) 30

Description for Correct answer:
Let the total quantity of mixture = x litre

According to question,

\( \frac{4}{4+1}=\left[ \frac{x-32}{x} \right] \)

4x=5x-160

x = 160 Litrs

The quantity of milk in mixture = \( 160 \times \frac{3}{4} \)

= 120 Litre

The quantity of water in misture = \( 160 \times \frac{1}{4} \)

= 40 Litre

32 litre of mixture was taken out and replaced with the same quantity of milk.

Then, the quantity of milk in mixture = \( 120-32 \times \frac{3}{4}+32 \)

= 120-24+32 = 128 Litre

After 10 litres of mixture is again taken out from the vessel, the resultant quantity of water

in the mixture = \( 32-10 \times \frac{1}{5} = 32 - 2 = 30 litre \)

Part of solved RBI Grade B questions and answers : Exams >> Bank Exams >> RBI Grade B

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