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# A vessel contains a mixture of milk and water in the respective ratio of 3 : 1. 32 litre of mixture was taken out and replaced with the same quantity of milk so that the resultant ratio between the quantities of milk and water in the mixture was 4 . : 1 respectively. If 10 litre of mixture is again taken out from the vessel, what is the resultant quantity of water in the mixture ? (in litre)

 A) 24 B) 30 C) 20 D) 36 E) 32

 B) 30

Let the total quantity of mixture = x litre

According to question,

$$\frac{4}{4+1}=\left[ \frac{x-32}{x} \right]$$

4x=5x-160

x = 160 Litrs

The quantity of milk in mixture = $$160 \times \frac{3}{4}$$

= 120 Litre

The quantity of water in misture = $$160 \times \frac{1}{4}$$

= 40 Litre

32 litre of mixture was taken out and replaced with the same quantity of milk.

Then, the quantity of milk in mixture = $$120-32 \times \frac{3}{4}+32$$

= 120-24+32 = 128 Litre

After 10 litres of mixture is again taken out from the vessel, the resultant quantity of water

in the mixture = $$32-10 \times \frac{1}{5} = 32 - 2 = 30 litre$$

Part of solved RBI Grade B questions and answers : Exams >> Bank Exams >> RBI Grade B

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