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Ajay can do a piece of work in 25 days and Sanjay can finish it in 20 days. They work together for 5 days and then Ajay goes away. In how many days will Sanjay finish the remaining work?


A) 11 days

B) 14 days

C) 12 days

D) None of these

Correct Answer:
A) 11 days

Description for Correct answer:

Ajay's 1 day's work = 1/25

Similarly, Sanjay's 1 day's work = 1/20

Ajay's and Sanjay's together 1 day's work

=\( \Large\frac{1}{25} + \frac{1}{20} = \frac{4 + 5}{100} = \frac{9}{100} \)

Their 5 day's work together = 5 x 1 day's work

=\( \Large 1 - \frac{45}{100} = \frac{55}{100} \)

Now, this remaining work is done by Sanjay.

Let Sanjay takes x days to complete it.

Then, \( \Large\frac{1}{20} \times x = \frac{55}{100} \)

\( \Large\frac{55 \times 20}{100} \)

X = 11 days

So, remaining work is done in 11 days by Sanjay.


Part of solved Time and work questions and answers : >> Aptitude >> Time and work




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