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A can do a piece of work in 10 days and B in 20 days. They begin together but A leaves 2 days before the completion of the work. The whole work will be done in


A) 8 days

B) 7 days

C) 7(2/3) days

D) 6 days

Correct Answer:
A) 8 days

Description for Correct answer:

Let the required days be x.





A works for (x - 2) days, while B works for x days.





According to the question,





\( \Large\frac{x - 2}{10} + \frac{x}{20} = 1 \)





2x- 4 + x = 20





3x = 24





x = 8 days




Part of solved Time and work questions and answers : >> Aptitude >> Time and work




Comments
Sir Why the following method is wrong...Bcz it's given that x can do 1/10 per day and y cn do 1/20 per day...Tougher thY cN do 3/20 per day Now before 3 days x left ... That means 3/20*2 =6/20 work is pending Then it will be done by y in (6/20) /1/20 days Ie 6 days Pls replay if any loicL mistake is there
- Pradeep,Varkala





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