There are 14 points in a plane, out of which 4 are collinear. Find the number of triangles made by these points.
Correct Answer: Description for Correct answer:
The required number of triangles = \( nC_3 � mC_3 \)
Here, n =14, m = 4
= \( 14C_3 � 4C_3 \)
=\( \large\frac{14 X 13 X 12 X 11!}{3! X 11!} - \frac{4!}{3! X 1!} \)
=\( \large\frac{14 \times 13 \times 12}{6} - \frac{4}{1} \)
=14 X 26 � 4 = 364 � 4 = 360
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