In how many different ways, the letters of the word 'ARMOUR' can be arranged?
Correct Answer: Description for Correct answer:
Number of arrangements = \( \large\frac{n!}{p! q! r!} \)
Total letters = 6, but R has come twice
So, required number of arrangements
= \( \large\frac{6!}{2!} = \frac{6 \times 5 \times 4 \times 3 \times 2!}{2!} = 360\)
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