Find the value of \( \Large \frac{log16-2log2+5log3-log27}{log4+log9} \)
Correct Answer: Description for Correct answer:
\( \Large log16-2log2+5log3-log27 \) \( \Large =4log2-2log2+5log3-3log3 \)
=\( \Large 2log2+2log3 \)
=\( \Large log4+log9 \)
\( \Large \frac{log16-2log2+5log3-log27}{log4+log9}=\frac{log4+log9}{log4+log9} \)
=\( \Large \frac{log36}{log36}=1 \)
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