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Find the value of \( \Large \frac{3log2+2log3}{2log6+log2} \)

A) 2
B) 6
C) 1
D) 4

Correct Answer:



C) 1

Description for Correct answer:
\( \Large 3log2+2log3=log2^{3}+log3^{2} \)

=\( \Large log8+log9 \)

=\( \Large log \left(8 \times 9\right)=log72 \)

\( \Large 2log6+log2=log6^{2}+log2 \)

=\( \Large log36+log2 \)

\( \Large \frac{3log2+2log3}{2log6+log2}=\frac{log72}{log72} \)

= 1

Part of solved Logarithms questions and answers : >> Elementary Mathematics >> Logarithms

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