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Find the value of \( \Large \frac{75}{16}-2log\frac{5}{9}+log\frac{32}{243} \)

A) log5
B) log4
C) log2
D) log3

Correct Answer:



C) log2

Description for Correct answer:
\( \Large log\frac{75}{16}-2log\frac{5}{9}+log\frac{32}{243}=log\frac{75}{16} \times \frac{9}{5} \times \frac{9}{5} \times \frac{32}{243} \)

= log2

Part of solved Logarithms questions and answers : >> Elementary Mathematics >> Logarithms

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