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If log2=0.3010 and log3=.04771. Find the value of log12

A) 0.7781
B) 1.0791
C) 0.9541
D) 0.602

Correct Answer:


B) 1.0791

Description for Correct answer:
\( \Large log 2=.3010,\ log3 =.4771 \)

\( \Large log_{12}=log \left(4 \times 3\right) \)

=\( \Large log4+log3 \)

=\( \Large log \left(2 \times 2\right)+log3 \)

=\( \Large log2+log2+log3 \)

=.3010+.3010+.4771

=1.0791

Part of solved Logarithms questions and answers : >> Elementary Mathematics >> Logarithms

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