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# If log2=0.3010 and log3=.04771. Find the value of log12

 A) 0.7781 B) 1.0791 C) 0.9541 D) 0.602

 B) 1.0791

$$\Large log 2=.3010,\ log3 =.4771$$

$$\Large log_{12}=log \left(4 \times 3\right)$$

=$$\Large log4+log3$$

=$$\Large log \left(2 \times 2\right)+log3$$

=$$\Large log2+log2+log3$$

=.3010+.3010+.4771

=1.0791

Part of solved Logarithms questions and answers : >> Elementary Mathematics >> Logarithms

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