Find the value of \( \Large log_{3}72-log_{3}8 \)
Correct Answer: Description for Correct answer:
\( \Large log_{3}72-log_{3}8 = log_{3} \left(9 \times 8\right)-log_{3}8 \)
=\( \Large log_{3}9+log_{3}8-log_{3}8 \)
=\( \Large log_{3}9 \)
=\( \Large log_{3}3^{2}=2log_{3}3 \)
=2
Part of solved Logarithms questions and answers :
>> Elementary Mathematics >> Logarithms