The number of g-molecule of oxygen in 6.02 x 1024CO molecules is


A) 1 gram of molecule

B) 0.5 gram of molecule

C) 5 gram of molecule

D) 10 gram of molecule

Correct Answer:
C) 5 gram of molecule

Description for Correct answer:

1 mole CO equivalent to \( 6.02 \times 10^23 \) molecules of CO contain \( 6.02 \times 10^23 \) atoms of Oxygen. 

So \( 6.02 \times 10^24\) CO molecules contain \( 6.02 \times 10^24\) atoms of O which is equivalent to 10 gm-atoms of oxygen. 

Since Oxygen is diatomic, 

10 g-atom = \(\frac{1}{2} \times 10\)g-molecule of Oxygen = 5 gram-molecule of O2 = 5 grams of O2 molecule.


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