A) 1 |
B) 2 |
C) 3 |
D) 4 |
C) 3 |
Using Remainder theorem put \( \Large x^4 = -1\) in \( \Large x^{40} +2\)
= > \( \Large \left( x^4 \right)^{10}\) + 2
= > \( \Large \left( -1 \right)^{10} \) +2
= > 1 + 2 = 3