If x + y + z = 13, then the maximum value of (x - 2 )(y + 1)(z - 3) is
Correct Answer: Description for Correct answer:
We know that, AM greater than equal to GM
\( \large\frac{(x - 2) + (y + 1) + (z - 3)}{3} \ge \sqrt[3]{(x - 2)(y + 1)(z - 3)} \)
= > \( \large\frac{13 - 4}{3} \ge \sqrt[3]{(x - 2)(y + 1)(z -3)} \)
= > \( \large 3 \ge \sqrt[3]{(x - 2)(y + 1)(z - 3)} \)
= >\( \large 27 \ge (x - 2)(y + 1)(z - 3) \)
Thus , maximum value of (x - 2)(y + 1)(z - 3) is 27.
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