A cricketer scored some runs in his continuous 9 innings. He scored 100 runs in his 10 th innings and increases his average by 8 runs. What was the average of his runs at the end of 10 th innings?
Correct Answer: Description for Correct answer:
Let the average of a inning = x.
Total runs = 9x.
According to the question, \( \large\frac{9x + 100}{10} = x + 8 \)
= > 9x + 100 = 10x +80
X = 20
Average after 10 innings = 20 + 8 = 28
Part of solved Average questions and answers :
>> Aptitude >> Average