A number lying between 1000 and 2000 is such that on division by 2, 3, 4, 5, 6, 7 and 8 leaves remainder respectively 1, 2, 3, 4, 5, 6 and 7. The number is


A) 1876

B) 1679

C) 1778

D) 1654

Correct Answer:
B) 1679

Description for Correct answer:
Note that =

=\( \Large \left(2-1\right)= \left(3-2\right)= \left(4-3\right) \) \( \Large = \left(5-4\right)= \left(6-5\right)= \left(7-6\right)= \left(8-7\right)=1 \)

LCM of 2, 3, 4, 5, 6, 7, 8 is 800

Required number = (840k-1)

Since the number lies between 1000 and 2000, the value of k=2

The number is 1680 - 12 = 1679.

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