Find the greatest 4 digit number which when divided by 15, 18, 21 and 27 leaves in each case a remainder 7.
Correct Answer: Description for Correct answer:
LCM of 15, 18, 21 and 27 is 1890.
\( \Large \frac{15,\ 18,\ 21,\ 27}{3},\ \frac{5,\ 6,\ 7,\ 9}{3} = 5,\ 2,\ 3,\ 7, \)
Greatest 4 digit number is 9999.
on dividing 9999 by 1890, we get the remainder 549
Therefore Greatest 4 digit number exactly divisible by
15, 18, 21 and 27 is
999 - 549 = 9450
Therefore, Required number is 9450 + 7 = 9457.
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