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# Find the greatest 4 digit number which when divided by 15, 18, 21 and 27 leaves in each case a remainder 7.

 A) 9457 B) 9547 C) 9947 D) 9967

 A) 9457

LCM of 15, 18, 21 and 27 is 1890.

$$\Large \frac{15,\ 18,\ 21,\ 27}{3},\ \frac{5,\ 6,\ 7,\ 9}{3} = 5,\ 2,\ 3,\ 7,$$

Greatest 4 digit number is 9999.

on dividing 9999 by 1890, we get the remainder 549

Therefore Greatest 4 digit number exactly divisible by

15, 18, 21 and 27 is

999 - 549 = 9450

Therefore, Required number is 9450 + 7 = 9457.

Part of solved LCM and HCF questions and answers : >> Elementary Mathematics >> LCM and HCF

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