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# The LCM of two numbers is 2310 and their HCF is 30. If one number is 210, the other number is

 A) 16170 B) 2100 C) 1470 D) 330

 D) 330

The other number = $$\Large \frac{LCM \times HCF}{The\ given\ number}$$

= $$\Large \frac{2310 \times 30}{210} = 11 \times 30 = 330$$

Part of solved LCM and HCF questions and answers : >> Elementary Mathematics >> LCM and HCF

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