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# The product of two numbers is 216 and their HCF is 27, then the numbers are

 A) 80, 136 B) 76, 14 C) 96, 25 D) 27, 189

 D) 27, 189

The sum of two numbers is 216 and their HCF is 27.

Let x and y be the numbers

$$\Large 27x+27y=216,\ x+y=8$$

The possible pairs are (1, 7) and (2, 6)

The Co. prime pairs is (1, 7)

The numbers are $$\Large \left(27 \times 1,\ 27 \times 7\right) = 27,\ 189$$

Part of solved LCM and HCF questions and answers : >> Elementary Mathematics >> LCM and HCF

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