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A) \( \Large \frac{41}{46} \) |

B) \( \Large \frac{46}{41} \) |

C) \( \Large \frac{21}{23} \) |

D) \( \Large \frac{21}{26} \) |

Correct Answer:

C) \( \Large \frac{21}{23} \) |

Description for Correct answer:

HCF of 1426 and 1302

HCF of 1426 and 1302 is 31

Divide the Nr and Dr by 31, we get

\( \Large \frac{1302}{1426}=\frac{42}{46}=\frac{21}{23} \)

\( \Large \frac{1426}{1302}, \frac{124}{31} = 0 \)

HCF of 1426 and 1302

HCF of 1426 and 1302 is 31

Divide the Nr and Dr by 31, we get

\( \Large \frac{1302}{1426}=\frac{42}{46}=\frac{21}{23} \)

\( \Large \frac{1426}{1302}, \frac{124}{31} = 0 \)

Part of solved LCM and HCF questions and answers : >> Elementary Mathematics >> LCM and HCF

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