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# The simplest form of $$\Large \frac{1302}{1426}$$ is

 A) $$\Large \frac{41}{46}$$ B) $$\Large \frac{46}{41}$$ C) $$\Large \frac{21}{23}$$ D) $$\Large \frac{21}{26}$$

 C) $$\Large \frac{21}{23}$$

HCF of 1426 and 1302

HCF of 1426 and 1302 is 31

Divide the Nr and Dr by 31, we get

$$\Large \frac{1302}{1426}=\frac{42}{46}=\frac{21}{23}$$

$$\Large \frac{1426}{1302}, \frac{124}{31} = 0$$

Part of solved LCM and HCF questions and answers : >> Elementary Mathematics >> LCM and HCF

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