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# $$\Large \frac{87}{261}$$ in the simplest form.

 A) $$\Large \frac{1}{2}$$ B) $$\Large \frac{1}{7}$$ C) $$\Large \frac{1}{3}$$ D) $$\Large \frac{1}{9}$$

 C) $$\Large \frac{1}{3}$$

HCF of 87 and 261 is 29

Divide the numerator and denominator by 29, we get $$\Large \frac{87}{261} = \frac{3}{9} =\frac{1}{3}$$

Part of solved LCM and HCF questions and answers : >> Elementary Mathematics >> LCM and HCF

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