Simplify \( \Large \frac{x^{2}+11x+30}{ \left(x^{2}+2x-15\right) } \)
Correct Answer: A) \( \Large \frac{x+6}{x-3} \) |
|
|
|
Description for Correct answer:
Factors of \( \Large x^{2}+11x+30= \left(x+6\right) \left(x+5\right) \)
Factors of \( \Large x^{2}+2x -15 = \left(x+5\right) \left(x-3\right) \)
\( \Large \frac{x^{2}+11x+30}{x^{2}+2x-15} - \frac{ \left(x+6\right) \left(x+5\right) }{ \left(x+5\right) \left(x-3\right) } = \frac{x+6}{x-3} \)
Part of solved Factorisation questions and answers :
>> Elementary Mathematics >> Factorisation