Find the factors of \( \Large x^{2}+10x+24 \)


A) \( \Large \left(x-6\right) \left(x-4\right) \)

B) \( \Large \left(x-6\right) \left(x+4\right) \)

C) \( \Large \left(x+6\right) \left(x-4\right) \)

D) \( \Large \left(x+6\right) \left(x+4\right) \)

Correct Answer:
D) \( \Large \left(x+6\right) \left(x+4\right) \)

Description for Correct answer:
\( \Large x^{2}+10x+24 = x^{2}+6x+4x+24 \)

=\( \Large x \left(x+6\right)+4 \left(x+6\right) \)

=\( \Large \left(x+6\right) \left(x+4\right) \)

Therefore, the factors of \( \Large x^{2}+10x+24 \) are =\( \Large \left(x+6\right) \left(x+4\right) \)

Part of solved Factorisation questions and answers : >> Elementary Mathematics >> Factorisation








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