Two pipes A and B can fill a cistern in 15 and 20 min, respectively. Both the pipes are opened together, but after 2 min, pipe A is turned off. What is the total time required to fill the tank?
Correct Answer: |
B) \( \Large \frac{52}{3} \) min |
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Description for Correct answer:
Part filled by both in 2 min = \( \Large 2x \left(\frac{1}{15}+\frac{1}{20}\right)=2x \left(\frac{4+3}{60}\right) \)
=\( \Large 2 \times \frac{7}{60}= \frac{7}{3} \)
Part unfilled = \( \Large 1 - \frac{7}{30}=\frac{30-7}{30}=\frac{23}{30} \)
Now, B fills \( \Large \frac{1}{20} \) part in 1 min.
Therefore, \( \Large \frac{23}{30} \) part will be filled by B In
= \( \Large \left(20 \times \frac{23}{30}\right)min\ or\ i\ \frac{46}{3}min \)
Therefore, Required time taken to fill the tank
=\( \Large \left(2+\frac{46}{3}\right)=\frac{52}{3}min. \)
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