Inlet A is four times faster than inlet B to fill a tank. If A alone can fill it in 15 min, how long will it take if both the pipes are opened together?
Correct Answer: Description for Correct answer:
Time taken by A to fill the tank, m = 15 min
Therefore, Time taken by B to fill the tank, n = \( \Large 15 \times 4 \) = 60 min
Therefore, Required time taken \( \Large \frac{m \times n}{m + n} \)
= \( \Large \frac{15 \times 60}{15 + 60}=\frac{15 \times 6}{75} \) = 12 min.
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