A tank has a leak which would empty it in 8 h. A tap is turned on which admits 3 L a min into the tank and it is now emptied in 12 h. How many litres does the tank hold?
Correct Answer: Description for Correct answer:
Work done by the inlet in 1 h
= \( \Large \left(\frac{1}{8}\right)-\frac{1}{12} = \frac{1}{24} \)
Work done by the inlet in 1 min 1 min
= \( \Large \frac{1}{24} \times \frac{1}{60}=\frac{1}{1440} \)
Therefore, Volume of \( \Large \frac{1}{1440} \) part = 3 L
Therefore, Volume of the whole
= \( \Large 3 \times 1440 \) = 4320 L
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