A pump can be used either to fill or to empty a tank. The capacity of the tank is 3600 \( \Large m^{2} \). The emptying capacity of the pump is 10 \( \Large \frac{m^{2}}{min} \) higher than its filling capacity. What is the emptying capacity of the pump if the pump needs 12 more minutes to fill the tank than it takes to empty the tank?
Correct Answer: |
B) \( \Large 60 m^{3}/min \) |
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Description for Correct answer:
\( \Large \frac{3600}{filling\ capacity}-\frac{3600}{emptying\ capacity}=12 \)
The question states that filling capacity of the pump =
emptying capacity - \( \Large 10 m^{2}/min. \)
Therefore, \( \Large \frac{1}{Emp.\ cap-10} - \frac{1}{Emp.\ cap}=\frac{1}{300} \)
Solving we get, Emptying capacity = \( \Large 60 m^{3}/min \)
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