A) 0 |
B) 4 |
C) 6 |
D) none of these |
A) 0 |
The vertices of quadrilateral ABCD is \( \Large A \left(2,\ 3\right),\ B \left(3,\ 4\right),\ C \left(4,\ 5\right)\ and\ D \left(5,\ 6\right) \)
AB = \( \Large \sqrt{ \left(3-2\right)^{2}+ \left(4-3\right)^{2} } = \sqrt{ \left(1\right)^{2}+ \left(1\right)^{2} }= \sqrt{2} \)
Similarly BC = \( \Large \sqrt{2},\ CD=\sqrt{2}\ and\ DA=3\sqrt{2} \)
\( \Large a = b = c = \sqrt{2}\ and\ d = 3\sqrt{2} \)
and \( \Large s=\frac{a+b+c+d}{2}=\frac{\sqrt{2}+\sqrt{2}+\sqrt{2}+3\sqrt{2}}{2} \)
= \( \Large \frac{6\sqrt{2}}{2} = 3\sqrt{2} \)
Therefore, Area of quadrilateral
= \( \Large \sqrt{ \left(s-a\right) \left(s-b\right) \left(s-c\right) \left(s-d\right) } \)
= \( \Large \sqrt{ \left(3\sqrt{2}-\sqrt{2}\right)\left(3\sqrt{2}-\sqrt{2}\right)\left(3\sqrt{2}-\sqrt{2}\right)\left(3\sqrt{2}-3\sqrt{2}\right) } = 0 \).