The points \( \Large \left(k,\ 2-2k\right) \), \( \Large \left(-k+1,\ 2k\right) \), \( \Large \left(-4-k,\ 6-2k\right) \) are collinear then k is equal to:
Correct Answer: |
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C) \( \Large \frac{1}{2},\ 1 \) |
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Part of solved Rectangular and Cartesian products questions and answers :
>> Elementary Mathematics >> Rectangular and Cartesian products