A) \( \Large 21 ^{\circ} \) |
B) \( \Large 42 ^{\circ} \) |
C) \( \Large 48 ^{\circ} \) |
D) \( \Large 84 ^{\circ} \) |
C) \( \Large 48 ^{\circ} \) |
AP is tangent to the circle at A. Therefore OA and AP are perpendicular to each other.
Therefore, \( \Large \angle OAP = 90 ^{\circ} \)
Again \( \Large OA\ =\ OB \)
Therefore, \( \Large \angle OAB = \angle OBA = 42 ^{\circ} \)
Therefore, \( \Large \angle PAB= \angle PAO - \angle BAO \)
= \( \Large 90 ^{\circ} - 42 ^{\circ} = 48 ^{\circ} \)