A) 15 cm |
B) 12 cm |
C) 10 cm |
D) 6 cm |
B) 12 cm |
From similar triangles ABC and DEF
\( \Large \frac{AB}{BC} = \frac{DE}{EF} \)
\( \Large \therefore \frac{AB}{20} = \frac{3}{5} \)
=> \( \Large AB = \frac{3 \times 20}{5} \) = 12 cm.