If \( \Large \cos \theta = \frac{1}{2} \left(x+\frac{1}{x}\right),\ then\ \frac{1}{2} \left(x^{2} + \frac{1}{x^{2}}\right) \) is equal to:


A) \( \Large \sin 2 \theta \)

B) \( \Large \sec 2 \theta \)

C) \( \Large \tan 2 \theta \)

D) \( \Large \cos 2 \theta \)

Correct Answer:
D) \( \Large \cos 2 \theta \)

Description for Correct answer:

Given that \( \Large \cos \theta = \frac{1}{2} \left(x+\frac{1}{x}\right) => x+\frac{1}{x}=2 \cos \theta \)

We know that \( \Large x^{2}+\frac{1}{x^{2}} = \left(x+\frac{1}{x}\right)^{2}-2 \)

= \( \Large \left(2 \cos \theta \right)^{2}-2=4 \cos^{2} \theta -2 \)

= \( \Large 2 \cos 2 \theta \) .. From (i)

Therefore, \( \Large \frac{1}{2} \left(x^{2}+\frac{1}{x^{2}}\right)=\frac{1}{2} \times 2 \cos \theta = \cos 2 \theta \)


Part of solved Trigonometric ratio questions and answers : >> Elementary Mathematics >> Trigonometric ratio








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