A) real and unequal |
B) real and equal |
C) imaginary |
D) none of these |
A) real and unequal |
The given equations are
\( \Large qx^{2}+px+q=0 \)
and \( \Large x^{2}-4qx+p_{2}=0 \)
Since, root of the equation (i) are complex, therefore \( \Large P^{2}-4q^{2}<0 \). Now, discriminant or equation (ii) is \( \Large 16q^{2}-4 P^{2}=-4 \left(P^{2}-4q^{2}\right)>0 \) Hence, roots are real and unequal.