A) \( \Large \frac{2}{\sqrt{5}} cm \) |
B) \( \Large \frac{4}{\sqrt{5}} cm \) |
C) \( \Large 2\sqrt{5} cm \) |
D) \( \Large 4\sqrt{5} cm \) |
D) \( \Large 4\sqrt{5} cm \) |
\( \Large 2 \left(length+breadth\right) =24 \)
=> \( \Large length\ + breadth\ =\ 12 \)
Therefore, Breadth = \( \Large \frac{1}{3} \times 12 =\ 4\ cm \)
and length = \( \Large \frac{2}{3} \times 12 =\ 8\ cm \)
Therefore, Diagonal of the rectangle
= \( \Large \sqrt{4^{2}+8^{2}}=\sqrt{16+64} \)
= \( \Large \sqrt{80} = 4\sqrt{5} cm \)