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The area of a rhombus is 120 \( \Large cm^{2} \). If one of its diagonals is of length 10 cm, then length of one of its sides is

A) 12 cm
B) 13 cm
C) 24 cm
D) \( \Large 2\sqrt{30} cm \)

Correct Answer:


B) 13 cm

Description for Correct answer:

Area of a rhombus = = \( \Large \frac{1}{2} \times Product\ of\ its\ diagonals. \)

Therefore, \( \Large 120 = \frac{1}{2} \times \left(d_{1} \times d_{2}\right) \) = \( \Large \frac{1}{2} \times \left(10 \times d_{2}\right) \) => Second diaghonal \( \Large \left(d_{2}\right)\ =\ 24\ cm \) From the figure, \( \Large AB = \sqrt{12^{2}+5^{2}}=\sqrt{169}=13 \)

Part of solved Mensuration questions and answers : >> Aptitude >> Mensuration

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