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Value of \( \Large \left(X^{b-c}\right)^{b+c},\ \left(X^{c-a}\right)^{c+a},\ \left(X^{a-b}\right)^{a+b} \) is


A) 0

B) X

C) 1

D) X+1

Correct Answer:
C) 1

Description for Correct answer:
\( \Large \left(X^{b-c}\right)^{b+c}. \left(X^{c-a}\right)^{c+a}. \left(X^{a-b}\right)^{a+b} \)

= \( \Large \left(X\right)^{ \left(b-c\right) \left(b+c\right)}. \left(X\right)^{ \left(c-a\right) \left(c+a\right) }. \left(X\right)^{ \left(a-b\right) \left(a+b\right) } \)

\( \Large X^{b^{2}-c^{2}}.X^{c^{2}-a^{2}}.X^{a^{2}-b^{2}} \)

= \( \Large X^{b^{2}-c^{2}+c^{2}-a^{2}+a^{2}-b^{2}} \)

=\( \Large X^{0} = 1 \)

Part of solved Polynomials questions and answers : >> Elementary Mathematics >> Polynomials




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