A) 4 |
B) 14 |
C) -4 |
D) -14 |
C) -4 |
Since\( \Large f(x) = x^{3} + 3x^{2} + Kx + 42 \) is divisible by
\( \Large x+3=x- \left(-3\right) \).
\( \Large \therefore f\left(-3\right)=0 \)
=> \( \Large \left(-3\right)^{3}-3 \left(-3\right)^{2}+k \left(-3\right)+42 = 0 \)
=> \( \Large -27-27-3k+42 = 0 \)
=> 3k + 12 = 0
=> k = -4