A) \( \Large \left(x-\frac{1}{2}\right) \) |
B) \( \Large \left(x+\frac{1}{2}\right) \) |
C) \( \Large \left(x-1\right) \) |
D) \( \Large \left(x+1\right) \) |
D) \( \Large \left(x+1\right) \) |
\( \Large f \left(x\right)=x^{3}+6x^{2}+11x+6 \)
But x = -1 makes \( \Large f \left(x\right)=0 \), therefore \( \Large x+1 \) must be factor of \( \Large f \left(x\right) \).