A) \( \Large -\frac{3}{5} \) |
B) \( \Large \frac{3}{5} \) |
C) \( \Large \frac{4}{5} \) |
D) \( \Large -\frac{4}{5} \) |
B) \( \Large \frac{3}{5} \) |
Given that, \( \Large tan \theta =\frac{P}{B}=\frac{3}{4} \) and
\( \Large 0 ^{\circ} <0<90 ^{\circ} \) (acute)
In \( \Large \triangle ABC \),
By, Pythagoras theorem
\( \Large BC^{2}=AC^{2}+AB^{2} \)
= 9 + 16 = 25
BC = 5
\( \Large sin \theta =\frac{P}{H}=\frac{3}{5} \)