A) AC and AB |
B) AC and BC |
C) BC and AC |
D) AB and AC |
C) BC and AC |
Let \( \Large \angle A = 2x \)
\( \Large \angle B = 4x \)
and \( \Large \angle C = 3x\)
We know, \( \Large \angle A \) + \( \Large \angle B \) + \( \Large \angle C \)= \( \Large 180 ^{\circ} \)
\( \Large \therefore 2x + 4x + 3x = \Large 180 ^{\circ} \)
=> \( \Large 9x = \Large 180 ^{\circ} \)
=> \( \Large x = \Large 20 ^{\circ} \)
Now, \( \Large \angle A = 40 ^{\circ} \)
\( \Large \angle B = 80 ^{\circ} \)
and \( \Large \angle C = 60 ^{\circ} \)
Hence, the shortest side of triangle = side opposite to the smallest angle
= BC and the longest side of triangle = side opposite to the longest angle = AC.