A circle of radius 10 cm has an equilateral triangle inscribed in it. The length of the perpendicular drawn from the centre to any side of the triangle is
Correct Answer: Description for Correct answer:
Circumradius =\( \Large \frac{2}{3}\times Height \)
Height =\( \Large \frac{10\times 3}{2} \)=15 cm
So,length of perpendicular drawn from centre = 15 - 10 = 5 cm
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