A) 6 cm |
B) 3.2 cm |
C) 3 cm |
D) 3.5 cm |
C) 3 cm |
Let original radius be r.
Then, according to the question,
\( \Large \pi (r+1)^{2}-\pi r^{2} \)=22
=> \( \Large \pi\times [(r+1)^{2}-r^{2}] \)=22
=> \( \Large \frac{22}{7}\times (r+1+r)(r+1-r) \)=22
=> 2r+1=7 => 2r=6
r=\( \Large \frac{6}{2} \)=3 cm