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A railing of 288 m is required for fencing a semi-circular park. Find the area of the park. \( \Large ( \pi = 22/7) \)

A) \( \Large 4928 m^{2} \)
B) \( \Large 9865 m^{2} \)
C) \( \Large 8956 m^{2} \)
D) \( \Large 9856 m^{2} \)

Correct Answer:

A) \( \Large 4928 m^{2} \)

Description for Correct answer:

Let the radius of the park be r, then

\( \Large \pi r+2r \)=288

\( \Large (\pi+2)r \)=288

=> \( \Large \left(\frac{22}{7}+2 \right)r \)=288

=> r=\( \Large \frac{288\times 7}{36} \)=56

Area of the park = \( \Large \frac{1}{2}\pi r^{2} \)

= \( \Large \frac{1}{2}\times \frac{22}{7} \times 56\times 56 \)

= 4928

Part of solved Area and perimeter questions and answers : >> Elementary Mathematics >> Area and perimeter

Comments

Similar Questions

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