The ratio of the length of the parallel sides of a trapezium is 3 : 2. The shortest distance between them is 15 cm. If the area of the trapezium is 450 sq cm, find the sum of the lengths of the parallel sides.
Correct Answer: Description for Correct answer:
Let the lengths of parallel sides an 3x and 2x.
We know that,
Area of trapezium = \( \Large \frac{1}{2} \) \( \Large (Sum \ of \ the \ parallel \ sides)\times Distance \ between \ them \)
\( \Large \frac{1}{2}(3x+2x)15=450 \)=>75x=900
x=\( \Large \frac{900}{75} \)=12 cm
Sum of the parallel sides = (3x + 2x)
= 5x = \( \Large 5\times 12 \)=60 cm
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