A) 8 |
B) 9 |
C) 10 |
D) 11 |
C) 10 |
Shaded part ABCD can be visualised as \( \Large \triangle ABD \) + \( \Large \triangle BCD \)
{where BD is common base and AB and CE are respective heights}
so, area can be calculated by finding the area of two triangles and adding them.
Area of shaded region
= Area of \( \Large \triangle ABD \) + Area of \( \Large \triangle BCD \)
=\( \Large \frac{1}{2}AB\times BD+\frac{1}{2}CE\times BD \)
= \( \Large \frac{1}{2}\times 3\times 4+\frac{1}{2}\times 2\times 4 \)=6+4
= 10 sq cm