The perimeter of two squares is 12 cm and 24 cm. The area of the bigger square is how many times that of the Smaller?
Correct Answer: Description for Correct answer:
We know that,
Perimeter of square = \( \Large 4\times Side \)
= \( \Large 4\times a \) = 12
=> a = 3
Area of smaller square
= \( \Large 3\times 3=9 cm^{2} \) ...(i)
Now, \( \Large 4\times b \) = 24
=> b = 6
Area of bigger square
= \( \Large 6\times 6=36 cm^{2}=4\times 9 cm^{2} \)
= \( \Large 4\times Area \) of smaller square [from Eq. (ii]
Heance area of bigger square is 4 times that of smaller square
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