The area of a rectangle lies between \( \Large \Large 40 cm^{2} \) and \( \Large \Large 45 cm^{2} \). If one of the sides is 5 cm, then its diagonal lies between
Correct Answer: Description for Correct answer:
Area of rectangle lies between \( \Large 40 cm^{2}\)
and \( \Large 45 cm^{2}\).
Now, one side = 5 cm
Since, area cannot be less than \( \Large 40 cm^{2}\)
Hence, other side cannot be less than
= \( \Large \frac{40}{5} \) = 8 cm
Since, area cannot be greater than \( \Large 45 cm^{2}\)
Hence, other side cannot be greater than
= \( \Large \frac{45}{5} \) = 9 cm
Minimum value of diagonal
= \( \Large \sqrt{8^{2}+5^{2}}=\sqrt{89} \) =9.43cm
Maximum value of diagonal
= \( \Large \sqrt{9^{2}+5^{2}}=\sqrt{106} \) = 10.3cm
Part of solved Area and perimeter questions and answers :
>> Elementary Mathematics >> Area and perimeter