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The product of two consecutive odd numbers is 19043. Which is the smaller one?

Correct Answer:

A) 137 |
B) 131 |

C) 133 |
D) 129 |

Correct Answer:

A) 137 |

Description for Correct answer:

Let the two consecutive odd numbers are x and x + 2.

According to the question,

\( \Large x \left(x+2\right)=19043 \)

\( \Large x^{2}+2x-19043=0 \)

\( \Large x^{2}+139x-137x-19043=0 \)

\( \Large x \left(x+139\right)-137 \left(x+139\right)=0 \)

\( \Large \left(x+139\right) \left(x-137\right)=0 \)

= x = 137, -139

x = 137 [ignore -ve sign]

So, the smallest one is 137.

Let the two consecutive odd numbers are x and x + 2.

According to the question,

\( \Large x \left(x+2\right)=19043 \)

\( \Large x^{2}+2x-19043=0 \)

\( \Large x^{2}+139x-137x-19043=0 \)

\( \Large x \left(x+139\right)-137 \left(x+139\right)=0 \)

\( \Large \left(x+139\right) \left(x-137\right)=0 \)

= x = 137, -139

x = 137 [ignore -ve sign]

So, the smallest one is 137.

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