The sum of five consecutive numbers is 190. What is the sum of the largest and the smallest numbers?
Correct Answer: Description for Correct answer:
Let the five consecutive numbers are x-2,x-1,x,x+ 1,x+ 2.
Sum of numbers = 190
Therefore, x - 2 + x - 1 + x + x + 1 + x + 2 = 190
= 5x = 190
Therefore, x = 38
Sum of largest and smallest numbers = 190
= x + 2 + x - 2 = 2x = \( \Large 2 \times 38 \) = 76
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