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The sum of five consecutive numbers is 190. What is the sum of the largest and the smallest numbers?

Correct Answer:

A) 75 |
B) 77 |

C) 76 |
D) 73 |

Correct Answer:

C) 76 |

Description for Correct answer:

Let the five consecutive numbers are x-2,x-1,x,x+ 1,x+ 2.

Sum of numbers = 190

Therefore, x - 2 + x - 1 + x + x + 1 + x + 2 = 190

= 5x = 190

Therefore, x = 38

Sum of largest and smallest numbers = 190

= x + 2 + x - 2 = 2x = \( \Large 2 \times 38 \) = 76

Let the five consecutive numbers are x-2,x-1,x,x+ 1,x+ 2.

Sum of numbers = 190

Therefore, x - 2 + x - 1 + x + x + 1 + x + 2 = 190

= 5x = 190

Therefore, x = 38

Sum of largest and smallest numbers = 190

= x + 2 + x - 2 = 2x = \( \Large 2 \times 38 \) = 76

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